# Number Series Practice and Tutorials

- Posted by Brian Stocker MA
- Date May 12, 2014
- Comments 4 comments

Number series are where a series of numbers are given and students must calculate either the missing numbers or the number that follows.

Standardized Tests such as the Ontario Police, Canadian Armed Forces Entrance Test, COOP, HSPT

See also number sequence (Algebra)

### Number Series Examples

An example is:

**Consider the following series: 26, 21, , 11, 6. What is the missing number?**

a. 27

b. 23

c. 16

d. 29

Looking carefully at the sequence, we can see right away that each number is 5 less than the previous number, so the missing number is 16.

We can re-write this sequence in mathematical notation as, a_{1}, a_{2}, a_{3},… a_{n}, where n is an integer and a_{n} is called its n^{th} term. And we can write the sequence in the form of a formula, where an integer is substituted in the place of the variable in the formula and the terms are obtained.

For example, let us consider the sequence 5,10,15,20,…

- Here, a
_{n}= 5n. The formula a_{n}= 5n. - The n
^{th}term of a sequence can be found by plugging n in the explicit formula for the sequence. So for example if we wanted to find the 100^{th}number in this sequence, we would substitute n=100 in the formula and get 500.

### Types of Number Sequence problems

**1. Simple addition or subtraction **– each number in the sequence is obtained by adding a number to the previous number.

For example, 2, 5, 8, 11, 14

Each number in the sequence is obtained by adding 3 to the previous number, which we could write as, a_{n+1} = a_{n} + 3.

**2. Simple multiplication – **each number in the sequence is obtained by multiplying the previous number by a whole number or fraction.

For example, 3, 9, 27, 81

Or,

20, 10, 5, 2.5

Each number in the first sequence is obtained by multiplying the previous number by 3, which we could write as, a_{n+1} = a_{n} X 3.

In the second example, each number in the series is the previous number divided by 2, or multiplied by ½, or a_{n+1} = a_{n} X 1/2.

**3. Prime Numbers – **each number in the sequence is a prime number.

For example,

23, , 31, 37

Answer: 29

**4. Operations on the previous two numbers**

For example,

8, 14, 22, 36, 58

Here the sequence is created by adding the previous 2 numbers.

**5. Exponents**

The number sequence is created by each number squared or cubed.

For example,

3, 9, 81, 6561, where each number is squared.

**6. Combining Sequences
**

2, 7, 13, 20, 28, 37

Here the sequence starts with 2, and each element is added to another sequence starting with 5. So, 2 + 5 = 7, 7 + 6 = 13, 13 + 7 = 20 and so on.

A variation is a sequence with a repeating element. For example,

1, 2, 3, 5, 7, 9, 12, 15

Here the sequence is, for each n, +1, +1, +1, +2, +2, +2, +3, +3,

**7. Fractions
**

For example,

**16/4, 4/2, 2/2, ½, ?**

Fractions are often meant to confuse. If fractions don`t have an obvious relationship, reduce them to lowest terms or to whole numbers. Reducing these to whole numbers, gives,

4, 2, 1, ½

Right away we can see the numbers are half the previous number, so the next in the series is ¼.

In this example, the answer is a fraction, however, you may have to reduce fractions to see the relation, and then convert back to get the answer in the correct form.

### Strategy for Answering Number Series Questions

Here is a quick method that will help you answer number

series.

For example:

2, 5, 6, 7, 8,

**Step 1** – glance at the series quickly and see if you can spot the pattern right away. First look for obvious differences – 2X, 5X, 1/2, 1/4 etc.

**Step 2** – Start analyzing. If you can’t find an obvious answer, get to work.

Take the different between the first 2 numbers and the different between the second 2 numbers.

2, (+3) 5, (+1) 6, (+1) 7, (+1) 8,

No clear pattern with a simple analysis. There is no addition,

subtraction, multiplication, division, fractional or exponent

relationship.

The relation must be a higher order or a second series.

Next look at the relation between the 1st number and the

2nd and the 1st and the 3rd. We see that,

1st + 3 = 5, 1st + 4 = 6. That’s it! The number 2 is added

to the sequence, 3, 4, 5, 6, so the next number will be 2 +

7 = 9.

### Practice Questions

**1. Consider the following series: 6, 12, 24, 48. What number should ****come next?**

a. 48

b. 64

c. 60

d. 96

**2. Consider the following series: 5, 6, 11, 17. What number should ****come next?**

a. 28

b. 34

c. 36

d. 27

**3. Consider the following series: 26, 21, …, 11, 6. What is the missing ****number?**

a. 27

b. 23

c. 16

d. 29

**4. Consider the following series:23, …, 31, 37. What is the missing ****number?**

a. 19

b. 27

c. 29

d. 30

**5. Consider the following series: 3, 6, 11, 18. What number should ****come next?**

a. 30

b. 27

c. 22

d. 29

**6. Consider the following series: 26, 24, 20, 14. What number should ****come next?**

a. 6

b. 18

c. 12

d. 8

**7. Consider the following series: 6, 8, 4, 10, 18, 22. What number ****should come next?**

a. 34

b. 32

c. 24

d. 26

**8. Consider the following series: L, O, R, …, X. What is the missing ****letter?**

a. S

b. U

c. T

d. M

**9. Consider the following series: X, Z, B, D. What letter should ****come next? **

a. E

b. F

c. G

d. H

**10. Consider the following series: 25, 33, 41, 49. What number ****should come next?**

a. 51

b. 55

c. 59

d. 57

### Answer Key

**1. D**

The numbers double each time.

**2. A**

Each number is the sum of the previous two numbers.

**3. C**

The numbers decrease by 5 each time.

**4. C**

The numbers are primes (divisible only by 1 and themselves).

**5. B**

The interval, beginning with 3, increases by 2 each time.

**6. A**

The interval, beginning with 2, increases by 2, and is subtracted each time.

**7. B**

Each number is the sum of the previous and the number 2 places to the

left.

**8. B**

There are two letters missing between each one, so U is next.

**9. B**

Miss a letter each time and ‘loop’ back, so F is next.

**10. D**

The numbers increase by 8.

**Written by**, Brian Stocker MA., Complete Test Preparation Inc.

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## 4 Comments

thank you (:

Are you open to explaining #7 a bit more? I am a bit confused by it. Thanks.

Here is the sequence 6, 8, 4, 10, 18, 22.

so – it is the sum of the number and the number 2 spaces back. Starting at 4 as we don’t know the number before 6, 6 + 4 = 10, then 8 + 10 = 18, and 22 + 10 = 32.

For number 4 I would say there is an alternate answer.

By assuming that the second number in the sequence is 27 (b) you can create a pattern in which the 3rd number is +8 bigger than the 1st, 4th is +10 bigger that the 2nd, and hypothetically the 5th number (43) is +12 bigger than the 3rd.

Just thought it was interesting.