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In algebra, a quadratic equation is any equation having the form where x represents an unknown, and a, b, and c represent known numbers such that a is not equal to 0. If a = 0, then the equation is linear, not quadratic.

Quadratic equations are usually called second degree equations, which mean that the second degree is the highest degree of the variable that can be found in the quadratic equation.

Solving Quadratic equations appear on most College standardized tests and some High School Proficiency exams

Quick tutorial Practice Questions Answer Key

How to Solve Quadratic Equations

**Method 1 – Factoring**

Quadratic equations are usually called second degree equations, which mean that the second degree is the highest degree of the variable that can be found in the quadratic equation. The form of these equations is:

where a, b and c are some real numbers.

One way for solving quadratic equations is the factoring method, where we transform the quadratic equation into a product of 2 or more polynomials. Let’s see how that works in one simple example:

Notice that here we don’t have parameter c, but this is still a quadratic equation, because we have the second degree of variable x. Our factor here is x, which we put in front and we are left with x+2. The equation is equal to 0, so either x or x+2 are 0, or both are 0.

So, our 2 solutions are 0 and -2.

**Method 2 – Quadratic formula**

If we are unsure how to rewrite quadratic equations so we can solve it using factoring method, we can use the formula for quadratic equation:

We write x_{1,2} because it represents 2 solutions of the equation. Here is a practice question :

We see that a is 3, b is -10 and c is 3.

We use these numbers in the equation and do some calculations.

Notice that we have + and -, so x_{1} is for + and x_{2} is for -, and that’s how we get 2 solutions.

**1. Find 2 numbers that sum to 21 and the sum of the ****squares is 261.**

a. 14 and 7

b. 15 and 6

c. 16 and 5

d. 17 and 4

2. Using the factoring method, solve the quadratic**equation: x ^{2} + 4x + 4 = 0**

a. 0 and 1

b. 1 and 2

c. 2

d. -2

**3. Using the quadratic formula, solve the quadratic****equation: x – 31/x = 0**

a. -?13 and ?13

b. -?31 and ?31

c. -?31 and 2?31

d. -?3 and ?3

**4. Using the factoring method, solve the quadratic****equation: 2x ^{2} – 3x = 0**

a. 0 and 1.5

b. 1.5 and 2

c. 2 and 2.5

d. 0 and 2

**5. Using the quadratic formula, solve the quadratic****equation: x ^{2} – 9x + 14 = 0**

a. 2 and 7

b. -2 and 7

c. -7 and –2

d. -7 and 2

**1. B**

The numbers are 15 and 6.

x + 7 = 21 => x = 21 -7

x^{2} + y^{2} = 261

(21 – 7 )^{2} + y^{2} = 261

441 – 42y + y^{2} + y^{2} = 261

2y^{2} – 42y + 180 = 0

y^{2} – 21y + 90 = 0

y_{1,2} = 21 + ?441 – 360/2

y_{1,2} = 21 + ?81/2

y_{1,2} = 21 + 9/2

y_{1} = 15

y2 = 6

x_{1} = 21 = y_{1} = 21 – 15 = 6

x_{2} = 21 – y_{2} = 21 – 6 = 15

**2. D**

-2

**3. B**

**4. A**

0 and 1.5

2x^{2} – 3x = 0

x(2x – 3)

x = 0 or 2x – 3 =0

x = 0 or x = 3/2

x = 0 or x = 1.5

**5. A**

2 and 7

**Written by:** **Modified: ** September 1st, 2018 September 1st, 2018

**Published:** April 6th, 2014